Trying Haskell

http://chestergrant.posterous.com/trying-out-haskell

by chegra84 • 15 years ago

37 35 15 years ago

chestergrant.posterous.com

ionfish• 15 years ago

Obligatory comment pointing out that the fabled "quicksort" example in Haskell is not actually quicksort proper since it's not in-place.

merijnv• 15 years ago

Not to mention that Haskell's sort function is actually quite a bit more complex than the stereotypical "quicksort" example shown.

aristidb• 15 years ago

C++'s std::sort in turn is a lot more complex than the quicksort example shown.

microtonal3• 15 years ago

For reference, Data.List.sort in GHC: http://www.haskell.org/ghc/docs/7.0.2/html/libraries/base-4....

It's still short and sweet ;).

chris_j• 15 years ago

Is it actually possible to implement quicksort in a pure functional language like Haskell (with immutable data structures)? Sorting in place would seem to involve mutating the list every time two values are swapped.

jmillikin• 15 years ago

Haskell has mutable data structures; you could easily implement in-place quicksort with vectors, arrays, or pointers.

Hemospectrum• 15 years ago

Haskell is designed to quarantine side effects, not remove them altogether. There's a special monad for building data structures that are mutable at creation time but appear immutable outside that block of code. In normal circumstances, you'd probably still have to copy the contents of the input into a new array before sorting it, though. So, it would still be less memory efficient on large inputs.

microtonal3• 15 years ago

Yes. For example, the vector package provides mutable arrays:

http://hackage.haskell.org/package/vector-0.7.0.1

Mutability is attained by using the ST monad. The ST monad uses mutable memory, but since it does not allow other interactions with the outside world, its value can be extracted (unlike the IO monad). When you are done with the modification of the vector, it can be frozen to obtain a pure vector.

The IO monad can also be used, but not if you want to return a pure value.

A good tutorial can be found at:

http://www.haskell.org/haskellwiki/Numeric_Haskell:_A_Vector...

I used mutable vectors in the ST monad in maximum entropy training software, and they are really performant.

stianan2• 15 years ago

Not only is it not proper quicksort, it's very memory inefficient.

eru3• 15 years ago

Depends on your GC and compiler.

KirinDave3• 15 years ago

Obligatory comment about quicksort being excessively popular because of its catchy name, and all-too-often delivering inferior performance on large datasets due to partial orderings & bad pivot choices.

Obligatory comment about how sorting algorithm speed is far more important when dealing with incredibly large datasets, spanning across multiple machines. Uninsightful (and perhaps glib) point about how Machines Are So Fast These Days that even Bubble Sort appears fast for medium-sized datasets.

Cleverly-worded comment about how Merge Sort is not the sort of sort to let you down in a jam, and how it is particularly suited to distributed computation (where the overhead of allocation is rendered meaningless by the I/O requirements).

megrimlock• 15 years ago

Genuine appreciation for concise recapitulation. I felt I could hear the Tivo fast-forward beep-boop sound while reading your comment.

Tiomaidh• 15 years ago

"Oh look, Haskell is great! Why? Static typing and concise code and no side effects!"

I don't disagree on any particular point, but this is hardly news (on HN, at least), and is rather lacking in substance.

microtonal3• 15 years ago

Indeed. Also, rewriting base library functionality is bad ;):

http://www.haskell.org/ghc/docs/7.0.2/html/libraries/base-4....

eru3• 15 years ago

Unless it's just an exercise or done for fun.

Peaker4• 15 years ago

Haskell's type system can also express interesting things most languages' type systems can't.

For example:

https://github.com/yairchu/red-black-tree/blob/master/AvlTre... -- in lines 13..21, an AVLTree type is defined -- with its invariants encoded in the type system. If there's a mistake in these 9 lines, you may get a wrong program. But the nice thing is that if you get just these 9 lines right -- then the hundreds of lines below it that implement an AVL tree cannot get the AVL invariants wrong.

The same is also true for Red Black Trees: https://github.com/yairchu/red-black-tree/blob/master/RedBla...

Lines 26..36 inclusive encode the RBTree type such that the invariants are enforced by the type-checker.

In case this is unclear: the type-checker enforcing the correctness of the invariants is at compile-time. A running program is a correct program, at least from the invariants' perspective.

billmcneale2• 15 years ago

This might be beautiful code but come on, not a single comment?

KirinDave3• 15 years ago

Comments: the great deceivers.

To paraphrase: Some people write tricky code and say, "Ah! I will use a comment to make this clear." Now they have two problems.

Peaker4• 15 years ago

You might be assuming a little much about the purpose and target audience of this code :-)

I didn't write it, by the way.

silentbicycle3• 15 years ago

See those type declarations? Those are comments. Comments that are automatically checked.

kd0amg• 15 years ago

How much does this much use of the type system's invariant enforcement increase compilation time? (still just getting into Haskell)

Zaak2• 15 years ago

That's a very interesting question. I made a stab at removing the invariant enforcement from the AVL tree code, but it was more involved than I expected.

In this specific case, it doesn't matter much since compilation takes less than a second on my underpowered netbook. I'm curious whether it's an issue for a program of significant size.

jbapple• 15 years ago

GADT are really cool, but I would like to note three caveats:

> in lines 13..21, an AVLTree type is defined -- with its invariants encoded in the type system

Its balance invariants are encoded, but its ordering invariants are not.

2. The code for manipulating AVL and red-black trees in GADT form is significantly more complicated that it would be if they were not in GADT form.

3. Sometimes, whether using GADTs or not, one ends up with code like this, from the AVL example:

> Nil -> undefined -- shouldnt happen

Needless to say, this negatively affects the comfort we might receive from the type system.

Having said all that, I think there are cases where GADTs are really worth the extra effort. Sometimes, they even simplify code when the alternative to GADTs is checking things at run-time!

Peaker4• 15 years ago

1. True, this is harder in Haskell. More easily possible in a language like Agda.

2. The assurances you get in return are probably worth it.

3. I think that piece is unnecessary, and the type system will see that constructor is impossible. If it doesn't, it's a limitation of Haskell GADT's, and can be fixed. I don't think you ever resort to "Nil -> undefined" in Agda.

pdhborges• 15 years ago

C++ quicksort :|

    #include <algorithm>
    #include <iterator>
    #include <functional>
    using namespace std;
 
    template <typename T>
    void sort(T begin, T end) {
        if (begin != end) {
            T middle = partition (begin, end,   bind2nd(less<iterator_traits<T>::value_type>(), *begin));
            sort (begin, middle);
            sort (max(begin + 1, middle), end);
        }
    }

from wikipedia

chc• 15 years ago

His version is explicit, sort of a C++ translation of the C algorithm (though still a bit longer than necessary even for C). I think he meant to imply "in simple C++ without STL." The awkwardness of partition() is not quite enough to overcome the LOC savings, but it's making a good effort.

The Haskell version also refrains from importing the equivalent Data.List, which would allow us to define `more` and `less` as simply `partition (< x) xs`.

Trying Haskell

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