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supernewton

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Dan and Lisa's answers agree on all but problems 6 and 9, and Dan got two more correct than Lisa. So Dan is correct on both 6 and 9. Therefore, Mary is incorrect on 6 and 9. So she got seven of the other eight correct, and Dan got three of the other eight correct. But on those eight problems, Mary and Dan disagree on only problems 2, 3, 5, and 10, therefore Mary got all four of those correct. Then Mary got three of problems 1, 4, 7, 8 correct, but everyone answered the same way on those, so Colin got three right on those problems as well. Then read off the deduced answer key for the other six problems to get Colin's final score.

Backyard Cyanide 1 year ago

Your body actually produces a small amount of cyanide endogenously, if it makes you feel any better. It has some role in cell signalling.

This is covered by the article. A board game might take 4 people and 2 hours to play. If your three friends didn't have fun with a board game the first time, they probably won't want to play again, and so you won't be able to play again either. Therefore there is a strong drive among boardgamers to play the "full" game the first time, because there might not be a second time.

It also adds extra difficulty to design a game that even has a simple version that is fun to play. Take your Texas Hold'em example, imagine it takes 2 hours to play one game. If you start with a version that has all cards face-up and no betting, people would conclude that Texas Hold'em is a supremely boring game, and wouldn't bother to try the full Texas Hold'em experience!

The conjecture is true for all small graphs that they tried, so if it's "obviously" false to you then something went wrong with your intuition somewhere.

For air transport in the U.S., it's not just one certificate, it's many. You get your private license, instrument rating, multi-engine rating, commercial certificate, instructor certificate, and finally the air transport certificate. And you're not allowed to even think about that last step until you've accumulated 1500 flight hours on the previous steps. Being allowed to write a Javascript login page is easy pickings compared to that.

Sure, but in practice there don't really seem to exist "natural" problems that are both in P and are worse than O(n^3) or so.

By "natural" I mean a problem that one would actually want to solve, not some contrived problem specifically to make it O(n^100) since that's obviously easily possible.

You don't get to have "hidden information". The code used to respond "yes" or "no" to the guess would be part of the problem input. But, we currently can't prove there doesn't exist some algorithm that can examine that code and figure out what the "yes" input is faster than brute forcing all inputs.

Ambiguous parses aren't even the worst of it -- the worst are the ones that require real world knowledge.

"I couldn't fit the trophy in my suitcase because it was too big."

"I couldn't fit the trophy in my suitcase because it was too small."

They're the feeder contests in the U.S. that determine who gets to represent the U.S. in the IMO.

AMC = multiple choice test, open to all grade school students.

AIME = open response test, all answers are numerical, open to students who score high enough on AMC only.

USAMO = USA Math Olympiad. IMO-style proof problems. Open only to top N scorers on AMC and AIME.

The U.S. has legislation limiting consumer liability of credit card fraud to $50, and many cards will further waive that to $0. It's just simply not the consumer's problem if someone copies their credit card number and uses it for fraud. They just have to call the bank to report the fraud, and then the bank will cancel the old card, issue a new one, and then it's the bank's problem on how to get the money back.

There are obviously commonsense exceptions granted.

Also, you can fulfill the swim requirement by taking 1 beginner swim class regardless of whether you actually learn to swim during that class or not.

If a and b are the golden ratio and its conjugate, then f_n = a^n + b^n. But since |b| < 1, you can just do f_n = nearest_integer(a^n).

Well, almost. You need to multiply by a factor of 1/sqrt(5) before rounding.