Consider, for example, calculating binomial coefficients mod a large number.
It's not hard to realise that C(n,k+1) = (n-k)C(n,k)/(k+1) is one way to write the binomial coefficients. So if we want to compute C(10^10,50309) mod 10^8, for example, we only ever really need to carry numbers mod 10^8 around. And since (ab) mod c = (a mob c)(b mod c) we can avoid obtaining really large numbers and can safely hold them in unsigned long ints.
Since this problem is counting things, there is mostly like a recurrence-type relationship to it and at each step you would take the result mod N. Many combinatorics problems are like this. Although if you've only done 60 PE problems, then the ones in the 400s somewhat implicitly assume you've done the previous 400 since the ideas do built up.