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felixN

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2048 Solver 12 years ago

I run 100 games - the algorithm needs 949 rounds in average to reach the 2048 tile

2048 Solver 12 years ago

Yes, true. I had the A* Algorithm in mind when I have implemented it, but the outcome really differs from that.

2048 Solver 12 years ago

You are right, the first cost function doesn't make a lot of sense, but I didn't divide by the number of leafs - so it basically also was based on the number of unassigned tiles.

So in the end you are right these approaches are more or less the same.