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IBM's monthly puzzle challenge

http://domino.research.ibm.com/Comm/wwwr_ponder.nsf/pages/index.html

by davyjones • 13 years ago

10 2 13 years ago

DO

domino.research.ibm.com

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2

akkartik• 13 years ago

I've been staring at the first problem from May '98. I understand the solution, but I still don't understand how it's possible.

alok-g• 13 years ago

It's because theta is so small. Considering a right triangle of height h and a much longer base, h must be quite large for the hypotenuse to be 6 m longer than the base. Below is a simple example:

base 1000 hypotenuse 1006 height 109.7087052

Right triangle here is of course an approximation to the original problem, just to demonstrate what is going on.

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